Find Answers
Get Study Tools
Get your homework help
23 Areas of Math We Help With
30k+ Questions answered
2 min avg time to find the answer
20b(4b3)3
10. What is the axis of symmetry for the parabola: y = − 2 ( x − 3 ) ( x − 7 )A) x=-2B) x=-3C) x=3D) x=511. Find the equation of a parabola in vertex form that passes through the point (7, 11) with vertex (5,-1)(A) y = 3 ( x − 5 ) 2 − 1(B) y = 1 12 ( x + 5 ) 2 − 1(C) y = − 3 ( x − 7 ) 2 + 11(D) y = 1 12 ( x + 7 ) 2 + 11
By using euler formula,one can obtain:2sin(π180)=((−1)1180)89−((−1)1180)91
See answers (1)
A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235m below. If the plane is traveling horizontally with a speed of 250 km/h (69.4m/s), (a) how far in advance of the recipients ( horizontal distance) must the goods be dropped. (b) Suppose, instead that the plane release the supplies a horizontal distance of 425m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climber's position? (c) with what speed do the supplies land in the latter case
Is the phase shift of −3sin(2x+π2)+1 equal to −π4 or just −π2?
See answers (2)
The theorem of existence and uniqueness is: Let y ′ + p ( x ) y = g ( x ) be a first order linear differential equation such that p(x) and g(x) are both continuous for a < x < b. Then there is a unique solution that satisfies it.When a differential equation has no solution that satisfies y ( x 0 ) = y 0 , what does this mean?? Can the theorem be verified??
Convert km/s into miles/hr 45 miles per hour to km/s a ) 7.2 × 10 1 k m / s b ) 2.6 × 10 5 k m / s c ) 2.0 × 10 − 2 k m / s d ) 2.8 × 10 1 k m / s e ) 7.7 × 10 − 3 k m / s
Double union notationThe Cantor set C is defined as C = [ 0 , 1 ] ∖ ⋃ n = 0 ∞ ⋃ k = 0 3 n − 1 ( 3 k + 1 3 n + 1 , 3 k + 2 3 n + 1 ) Does the double union of sets work like the double summation?I start counting from n = 0 and then all of the k's.I.e.For n = 0...0, k goes from 0 to 0 ⋃ n = 0 0 ⋃ k = 0 0 = ( 1 3 , 2 3 ) For n = 1, k = 0...2. ⋃ n = 0 1 ⋃ k = 0 2 = ( 1 3 , 2 3 ) ∪ ( 3 ⋅ 0 + 1 3 1 + 1 , 3 ⋅ 0 + 2 3 1 + 1 ) ∪ ( 3 ⋅ 1 + 1 3 1 + 1 , 3 ⋅ 1 + 2 3 1 + 1 ) ∪ ( 3 ⋅ 2 + 1 3 1 + 1 , 3 ⋅ 2 + 2 3 1 + 1 ) = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 4 9 , 5 9 ) ∪ ( 7 9 , 8 9 ) = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 7 9 , 8 9 ) For n = 2, k = 0...8 ⋃ n = 0 2 ⋃ k = 0 8 = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 7 9 , 8 9 ) ∪ ( 3 ⋅ 0 + 1 3 2 + 1 , 3 ⋅ 0 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 1 + 1 3 2 + 1 , 3 ⋅ 1 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 2 + 1 3 2 + 1 , 3 ⋅ 2 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 3 + 1 3 2 + 1 , 3 ⋅ 3 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 4 + 1 3 2 + 1 , 3 ⋅ 4 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 5 + 1 3 2 + 1 , 3 ⋅ 5 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 6 + 1 3 2 + 1 , 3 ⋅ 6 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 7 + 1 3 2 + 1 , 3 ⋅ 7 + 2 3 2 + 1 ) ( 3 ⋅ 8 + 1 3 2 + 1 , 3 ⋅ 8 + 2 3 2 + 1 ) = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 7 9 , 8 9 ) ∪ ( 1 27 , 2 27 ) ∪ ( 4 27 , 5 27 ) ∪ ( 7 27 , 8 27 ) ∪ ( 10 27 , 11 27 ) ∪ ( 13 27 , 14 27 ) ∪ ( 16 27 , 17 27 ) ∪ ( 19 27 , 20 27 ) ∪ ( 22 27 , 23 27 ) ∪ ( 25 27 , 26 27 ) = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 7 9 , 8 9 ) ∪ ( 1 27 , 2 27 ) ∪ ( 7 27 , 8 27 ) ∪ ( 19 27 , 20 27 ) ∪ ( 25 27 , 26 27 ) For n = 3, k = 0...26.
Bounding a logarithmic relationIf I have the following relation T ( n ) ≤ a n ⌈ lg ( n ) ⌉ − a n + 2 b n + n, is it possible to bound T ( n ) such that it is in the form T ( n ) ≤ a n lg ( n ) + b n for some constants a , b ≥ 0?
Prices starting at $5/week., cancel anytime
Step-by-step solutions on your subject developed by experts