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20b(4b3)3
If 3 ordinary coins are tossed, write out a sample space. Part of the sample space is the. Type 3 more outcomes for the sample.
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For the experiment of tossing a coin three times, how do you find the probability of getting a head on the first toss?
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Find the direction cosines of the a vector in the plane of b → =< 2 , 1 , 3 > and c → =< − 1 , 2 , 1 > and perpendicular to c → Let the vector a → = ⟨ x , y , z ⟩Since it is perpendicular to c → − x + 2 y + z = 0And | x y z 2 1 3 − 1 2 1 | ⟹ − 5 x − 7 y + 5 z = 0since a, b, c are coplanarSo y=0Then x=ySo the answer should be ⟨ 1 2 , 0 , 1 2 ⟩ , but that is not correct.What is wrong with my solution?
Find the domain of the function. f ( x ) = 8 + x 9 − 2 x
Finding Multiple regression coefficientsIf I have a multiple regression like this Y = a + b 1 . X 1 + b 2 . X 2 , how can I calculate the values of b 1 and b 2 ? I have searched on the web but couldn't find an answer.
If I toss a coin 3 times and want to know the probability of at least one head, I have understood that the answer is 1 − 0.5 3 = 99 %. However, why cannot I not use the additon rule P ( A ∪ B ) = P ( A ) + P ( B ) − P ( A ∩ B ), i.e. 0.5 + 0.5 + 0.5 − 0.5 3 ?
To solve: n+18−2−n3=56
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How to graph y = 4 x + 4 ?
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