Find Answers
Get Study Tools
Get your homework help
23 Areas of Math We Help With
30k+ Questions answered
2 min avg time to find the answer
20b(4b3)3
What's U in Physics?
See answers (1)
Integrate ∫ x e − 5 x d x
How to solve this particular system of linear equations? [ 1 0 0 − 1 2 0 1 0 2 − 3 0 0 1 − 1 2 ]
See answers (2)
Logarithm multiplication property error, can't figure out why.I know there is a mistake and where it is but I can't figure out why.Equation: 3 + 2 ( 12 x + 1 ) = 291From here I do: 2 ( 12 x + 1 ) = 291 − 3 2 ( 12 x + 1 ) = 288 Then I take the natural logarithms on both sides; ln ( 2 ∗ 12 x + 1 ) = ln ( 288 ) ln ( 2 ∗ 12 x + 1 ) = ln ( 2 ∗ 12 2 ) Now I apply multiplication property so ln ( a ∗ b ) should equal ln ( a ) + ln ( b ) But here it seems that I'm making a mistake, can't figure out why: ln ( 2 ) + ln ( 12 x + 1 ) = ln ( 2 ) + ln ( 12 2 ) subtract ln ( 2 ) on both sides: ln ( 12 x + 1 ) = ln ( 12 2 ) Then it should be: ( x + 1 ) ln ( 12 ) = 2 ln ( 12 ) x + 1 = 2 x = 1 but it's not the right result..Thanks in advance :)
Let f : R m → R n be a linear transformation. As is common knowledge, it can be expressed as an n × m matrix.
I had this question when I was shopping for some rates to refinance my house: how do know if I have found the lowest rates after searching through a bunch of offers with a reasonable amount of confidence, in a mathematical/statistical term. For example, if found "x" offers from different vendors, is the amount of "x" large enough to represent the bigger population i.e. all offers out there?The reason I am asking is that I vaguely remember there are statistical sampling techniques from college days that survey companies used to represent the bigger populations. For instance, after surveying 2000 people, they can conclude something for the U.S. population. In other words, they "know" 2000 people can represent the U.S. population with some scientific backing.Just curious, if there is a way to figure out the magical number "x", then I can go with the lowest rate after browsing through "x" vendors as well. The question is purely theoretical in this simple case: the lowest rate wins. Any leads or ideas are appreciated.
Double union notationThe Cantor set C is defined as C = [ 0 , 1 ] ∖ ⋃ n = 0 ∞ ⋃ k = 0 3 n − 1 ( 3 k + 1 3 n + 1 , 3 k + 2 3 n + 1 ) Does the double union of sets work like the double summation?I start counting from n = 0 and then all of the k's.I.e.For n = 0...0, k goes from 0 to 0 ⋃ n = 0 0 ⋃ k = 0 0 = ( 1 3 , 2 3 ) For n = 1, k = 0...2. ⋃ n = 0 1 ⋃ k = 0 2 = ( 1 3 , 2 3 ) ∪ ( 3 ⋅ 0 + 1 3 1 + 1 , 3 ⋅ 0 + 2 3 1 + 1 ) ∪ ( 3 ⋅ 1 + 1 3 1 + 1 , 3 ⋅ 1 + 2 3 1 + 1 ) ∪ ( 3 ⋅ 2 + 1 3 1 + 1 , 3 ⋅ 2 + 2 3 1 + 1 ) = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 4 9 , 5 9 ) ∪ ( 7 9 , 8 9 ) = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 7 9 , 8 9 ) For n = 2, k = 0...8 ⋃ n = 0 2 ⋃ k = 0 8 = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 7 9 , 8 9 ) ∪ ( 3 ⋅ 0 + 1 3 2 + 1 , 3 ⋅ 0 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 1 + 1 3 2 + 1 , 3 ⋅ 1 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 2 + 1 3 2 + 1 , 3 ⋅ 2 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 3 + 1 3 2 + 1 , 3 ⋅ 3 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 4 + 1 3 2 + 1 , 3 ⋅ 4 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 5 + 1 3 2 + 1 , 3 ⋅ 5 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 6 + 1 3 2 + 1 , 3 ⋅ 6 + 2 3 2 + 1 ) ∪ ( 3 ⋅ 7 + 1 3 2 + 1 , 3 ⋅ 7 + 2 3 2 + 1 ) ( 3 ⋅ 8 + 1 3 2 + 1 , 3 ⋅ 8 + 2 3 2 + 1 ) = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 7 9 , 8 9 ) ∪ ( 1 27 , 2 27 ) ∪ ( 4 27 , 5 27 ) ∪ ( 7 27 , 8 27 ) ∪ ( 10 27 , 11 27 ) ∪ ( 13 27 , 14 27 ) ∪ ( 16 27 , 17 27 ) ∪ ( 19 27 , 20 27 ) ∪ ( 22 27 , 23 27 ) ∪ ( 25 27 , 26 27 ) = ( 1 3 , 2 3 ) ∪ ( 1 9 , 2 9 ) ∪ ( 7 9 , 8 9 ) ∪ ( 1 27 , 2 27 ) ∪ ( 7 27 , 8 27 ) ∪ ( 19 27 , 20 27 ) ∪ ( 25 27 , 26 27 ) For n = 3, k = 0...26.
The bisector of an equilateral triangle is 11 3 . find his side
Prices starting at $5/week., cancel anytime
Step-by-step solutions on your subject developed by experts