## Example 1:

### Solution:

Suppose you flip a coin. What is the chance Heads will appear?

50% (i.e. 1/2)

What is the chance that tails will appear?50% (i.e. 1/2)

## Example 2:

Toss a dice. What is the probability that an even number will appear?

### Solution:

The six numbers on a dice are 1, 2, 3, 4, 5, 6.

On the dice, 2, 4 and 6 are the even numbers.

So, the probability an even number will fall is 3/6 i.e. ½

## Example 3:

In a bag, there are 3 green and 4 red marbles. Take out any two marbles out of the bag. What is the probability the two marbles are green-colored?

### Solution:

Bag contains 7 marbles. 2 marbles are taken out. 2 out of 7 can be taken out in 7c2 ways i.e. 21 ways. (Recall that r things can be selected out of n things in ncr ways from combinations). 2 green out of 3 green marbles can be taken out in 3c2 ways i.e. 3 ways. The probability is therefore:

3/21 = 1/7.From the three examples above, we can define probability as follows: If E denotes an event, then the probability Event E will happen is: P (E) = (Outcomes favorable for E)/ (Total number of outcomes). The table below summaries the salient points in the 3 examples above.

So, try a definition for Probability? Here we go:

Let E denote an Event and P (E) the probability that Event E will happen. Then, P (E) = (Number of outcomes favorably for E)/(Total number of outcomes)

Solved Examples:

Five coins are tossed. Find the probability of: 3 heads; At least 3 heads; At most 2 heads; 3 heads, exactly next to each other.

### Solution:

Use the above formula: P (E) = (Number of outcomes favorable for E)/(Total number of outcomes)

First find the total number of outcomes when 5 coins are tossed.

It is 2 × 2 × 2 × 2 × 2 × 2 = 25 = 32outcomes and not2 × 5 = 10outcomes.

(If 3 coins are tossed, the total number of outcomes is2 × 2 × 2 = 8outcomes and not

2 × 3 = 6outcomes.)How, as follows:So, 3 coins give

2 × 2 × 2 = 23 = 8outcomes.

Likewise, 5 coins give2 × 2 × 2 × 2 × 2 = 25 = 32outcomes.

Now, how many outcomes show 3 heads out of 32?

5c3 i.e. 10 outcomes. How? As follows:

The dots indicate Tails. Tabulating is difficult.You must use an easier way to find favorable outcomes, with a formula probably.

And it is combinations formula: ncr

We need 3 Heads. Which 3 coins must show the required 3 Heads?

Any 3 coins. So, select any 3 coins out of the 5 coins. In how many ways?

Yes, in ncr ways, i.e. 5c3 ways i.e. 10 ways. Each way is one outcome, 10 ways are 10 outcomes.

So, the probability 3 Heads will appear is= 10/32 = 5/16

**Probability of at least 3 Heads: **At least 3 heads means minimum 3 heads i.e. 3 or more heads i.e. 3 or 4 or 5 heads.

**So, find probability of the following events: **3 heads or 4 Heads or 5 Heads

So, P (At least 3 Heads) = P (3H) or P (4H) or P (5H) (Remember one rule: Write + for Or when it needs to used and × for And)

So, P (At least 3 Heads) = P (3H) + P (4H) + P (5H) (0.5 and 0.5)

**Probability of at most 2 Heads:**

At most means maximum 2 heads i.e. up to 2 heads, i.e. less than or equal to 2 heads.

So, find probability of the following events: 2 Heads or 1 Heads or No Heads.

So, P (At most 2 Heads) = P (2H) + P (1H) + P (0H) (0.5 and 0.5)

**Probability of exactly 3 Heads, next to each other.**

**Dots indicate tails.**

We must tabulate the outcomes that give 3 Heads as it is a special case.

P (3 Heads, next to each other) = 3/32

(Note: In the first row, 5th coin cannot show a Heads, for we need only 3 Heads and the series 5th, 1st and 2nd coin is not acceptable for Heads to fall next to each other).